Question
Find Greatest Common Divisor of 710 and 310, using prime factorization.
Answer
The GCD of given numbers is 10.
Explanation
Step 1 : Find prime factorization of each number.
$$\begin{aligned}710 =& 2\cdot5\cdot71\\[8pt]310 =& 2\cdot5\cdot31\\[8pt]\end{aligned}$$(view steps on how to factor 710 and 310. )
Step 2 : Put a box around factors that are common for all numbers:
$$\begin{aligned}710 =& \color{blue}{\boxed{2}}\cdot\color{red}{\boxed{5}}\cdot71\\[8pt]310 =& \color{blue}{\boxed{2}}\cdot\color{red}{\boxed{5}}\cdot31\\[8pt]\end{aligned}$$Step 3 : Multiply the boxed numbers together:
$$ GCD = 2\cdot5 = 10 $$This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.
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