The GCD of given numbers is 10.
Step 1 : Find prime factorization of each number.
$$\begin{aligned}15210 =& 2\cdot3\cdot3\cdot5\cdot13\cdot13\\[8pt]10210 =& 2\cdot5\cdot1021\\[8pt]\end{aligned}$$(view steps on how to factor 15210 and 10210. )
Step 2 : Put a box around factors that are common for all numbers:
$$\begin{aligned}15210 =& \color{blue}{\boxed{2}}\cdot3\cdot3\cdot\color{red}{\boxed{5}}\cdot13\cdot13\\[8pt]10210 =& \color{blue}{\boxed{2}}\cdot\color{red}{\boxed{5}}\cdot1021\\[8pt]\end{aligned}$$Step 3 : Multiply the boxed numbers together:
$$ GCD = 2\cdot5 = 10 $$This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.