The GCD of given numbers is 1.
Step 1 :
Divide $ 9973 $ by $ 6393 $ and get the remainder
The remainder is positive ($ 3580 > 0 $), so we will continue with division.
Step 2 :
Divide $ 6393 $ by $ \color{blue}{ 3580 } $ and get the remainder
The remainder is still positive ($ 2813 > 0 $), so we will continue with division.
Step 3 :
Divide $ 3580 $ by $ \color{blue}{ 2813 } $ and get the remainder
The remainder is still positive ($ 767 > 0 $), so we will continue with division.
Step 4 :
Divide $ 2813 $ by $ \color{blue}{ 767 } $ and get the remainder
The remainder is still positive ($ 512 > 0 $), so we will continue with division.
Step 5 :
Divide $ 767 $ by $ \color{blue}{ 512 } $ and get the remainder
The remainder is still positive ($ 255 > 0 $), so we will continue with division.
Step 6 :
Divide $ 512 $ by $ \color{blue}{ 255 } $ and get the remainder
The remainder is still positive ($ 2 > 0 $), so we will continue with division.
Step 7 :
Divide $ 255 $ by $ \color{blue}{ 2 } $ and get the remainder
The remainder is still positive ($ 1 > 0 $), so we will continue with division.
Step 8 :
Divide $ 2 $ by $ \color{blue}{ 1 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 1 }} $.
We can summarize an algorithm into a following table.
| 9973 | : | 6393 | = | 1 | remainder ( 3580 ) | ||||||||||||||
| 6393 | : | 3580 | = | 1 | remainder ( 2813 ) | ||||||||||||||
| 3580 | : | 2813 | = | 1 | remainder ( 767 ) | ||||||||||||||
| 2813 | : | 767 | = | 3 | remainder ( 512 ) | ||||||||||||||
| 767 | : | 512 | = | 1 | remainder ( 255 ) | ||||||||||||||
| 512 | : | 255 | = | 2 | remainder ( 2 ) | ||||||||||||||
| 255 | : | 2 | = | 127 | remainder ( 1 ) | ||||||||||||||
| 2 | : | 1 | = | 2 | remainder ( 0 ) | ||||||||||||||
| GCD = 1 | |||||||||||||||||||
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.