The GCD of given numbers is 1.
Step 1 :
Divide $ 6828 $ by $ 709 $ and get the remainder
The remainder is positive ($ 447 > 0 $), so we will continue with division.
Step 2 :
Divide $ 709 $ by $ \color{blue}{ 447 } $ and get the remainder
The remainder is still positive ($ 262 > 0 $), so we will continue with division.
Step 3 :
Divide $ 447 $ by $ \color{blue}{ 262 } $ and get the remainder
The remainder is still positive ($ 185 > 0 $), so we will continue with division.
Step 4 :
Divide $ 262 $ by $ \color{blue}{ 185 } $ and get the remainder
The remainder is still positive ($ 77 > 0 $), so we will continue with division.
Step 5 :
Divide $ 185 $ by $ \color{blue}{ 77 } $ and get the remainder
The remainder is still positive ($ 31 > 0 $), so we will continue with division.
Step 6 :
Divide $ 77 $ by $ \color{blue}{ 31 } $ and get the remainder
The remainder is still positive ($ 15 > 0 $), so we will continue with division.
Step 7 :
Divide $ 31 $ by $ \color{blue}{ 15 } $ and get the remainder
The remainder is still positive ($ 1 > 0 $), so we will continue with division.
Step 8 :
Divide $ 15 $ by $ \color{blue}{ 1 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 1 }} $.
We can summarize an algorithm into a following table.
| 6828 | : | 709 | = | 9 | remainder ( 447 ) | ||||||||||||||
| 709 | : | 447 | = | 1 | remainder ( 262 ) | ||||||||||||||
| 447 | : | 262 | = | 1 | remainder ( 185 ) | ||||||||||||||
| 262 | : | 185 | = | 1 | remainder ( 77 ) | ||||||||||||||
| 185 | : | 77 | = | 2 | remainder ( 31 ) | ||||||||||||||
| 77 | : | 31 | = | 2 | remainder ( 15 ) | ||||||||||||||
| 31 | : | 15 | = | 2 | remainder ( 1 ) | ||||||||||||||
| 15 | : | 1 | = | 15 | remainder ( 0 ) | ||||||||||||||
| GCD = 1 | |||||||||||||||||||
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.