The GCD of given numbers is 1.
Step 1 :
Divide $ 6751 $ by $ 5436 $ and get the remainder
The remainder is positive ($ 1315 > 0 $), so we will continue with division.
Step 2 :
Divide $ 5436 $ by $ \color{blue}{ 1315 } $ and get the remainder
The remainder is still positive ($ 176 > 0 $), so we will continue with division.
Step 3 :
Divide $ 1315 $ by $ \color{blue}{ 176 } $ and get the remainder
The remainder is still positive ($ 83 > 0 $), so we will continue with division.
Step 4 :
Divide $ 176 $ by $ \color{blue}{ 83 } $ and get the remainder
The remainder is still positive ($ 10 > 0 $), so we will continue with division.
Step 5 :
Divide $ 83 $ by $ \color{blue}{ 10 } $ and get the remainder
The remainder is still positive ($ 3 > 0 $), so we will continue with division.
Step 6 :
Divide $ 10 $ by $ \color{blue}{ 3 } $ and get the remainder
The remainder is still positive ($ 1 > 0 $), so we will continue with division.
Step 7 :
Divide $ 3 $ by $ \color{blue}{ 1 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 1 }} $.
We can summarize an algorithm into a following table.
| 6751 | : | 5436 | = | 1 | remainder ( 1315 ) | ||||||||||||
| 5436 | : | 1315 | = | 4 | remainder ( 176 ) | ||||||||||||
| 1315 | : | 176 | = | 7 | remainder ( 83 ) | ||||||||||||
| 176 | : | 83 | = | 2 | remainder ( 10 ) | ||||||||||||
| 83 | : | 10 | = | 8 | remainder ( 3 ) | ||||||||||||
| 10 | : | 3 | = | 3 | remainder ( 1 ) | ||||||||||||
| 3 | : | 1 | = | 3 | remainder ( 0 ) | ||||||||||||
| GCD = 1 | |||||||||||||||||
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.