The GCD of given numbers is 2.
Step 1 :
Divide $ 98 $ by $ 54 $ and get the remainder
The remainder is positive ($ 44 > 0 $), so we will continue with division.
Step 2 :
Divide $ 54 $ by $ \color{blue}{ 44 } $ and get the remainder
The remainder is still positive ($ 10 > 0 $), so we will continue with division.
Step 3 :
Divide $ 44 $ by $ \color{blue}{ 10 } $ and get the remainder
The remainder is still positive ($ 4 > 0 $), so we will continue with division.
Step 4 :
Divide $ 10 $ by $ \color{blue}{ 4 } $ and get the remainder
The remainder is still positive ($ 2 > 0 $), so we will continue with division.
Step 5 :
Divide $ 4 $ by $ \color{blue}{ 2 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 2 }} $.
We can summarize an algorithm into a following table.
| 98 | : | 54 | = | 1 | remainder ( 44 ) | ||||||||
| 54 | : | 44 | = | 1 | remainder ( 10 ) | ||||||||
| 44 | : | 10 | = | 4 | remainder ( 4 ) | ||||||||
| 10 | : | 4 | = | 2 | remainder ( 2 ) | ||||||||
| 4 | : | 2 | = | 2 | remainder ( 0 ) | ||||||||
| GCD = 2 | |||||||||||||
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.