The GCD of given numbers is 1.
Step 1 :
Divide $ 625 $ by $ 512 $ and get the remainder
The remainder is positive ($ 113 > 0 $), so we will continue with division.
Step 2 :
Divide $ 512 $ by $ \color{blue}{ 113 } $ and get the remainder
The remainder is still positive ($ 60 > 0 $), so we will continue with division.
Step 3 :
Divide $ 113 $ by $ \color{blue}{ 60 } $ and get the remainder
The remainder is still positive ($ 53 > 0 $), so we will continue with division.
Step 4 :
Divide $ 60 $ by $ \color{blue}{ 53 } $ and get the remainder
The remainder is still positive ($ 7 > 0 $), so we will continue with division.
Step 5 :
Divide $ 53 $ by $ \color{blue}{ 7 } $ and get the remainder
The remainder is still positive ($ 4 > 0 $), so we will continue with division.
Step 6 :
Divide $ 7 $ by $ \color{blue}{ 4 } $ and get the remainder
The remainder is still positive ($ 3 > 0 $), so we will continue with division.
Step 7 :
Divide $ 4 $ by $ \color{blue}{ 3 } $ and get the remainder
The remainder is still positive ($ 1 > 0 $), so we will continue with division.
Step 8 :
Divide $ 3 $ by $ \color{blue}{ 1 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 1 }} $.
We can summarize an algorithm into a following table.
| 625 | : | 512 | = | 1 | remainder ( 113 ) | ||||||||||||||
| 512 | : | 113 | = | 4 | remainder ( 60 ) | ||||||||||||||
| 113 | : | 60 | = | 1 | remainder ( 53 ) | ||||||||||||||
| 60 | : | 53 | = | 1 | remainder ( 7 ) | ||||||||||||||
| 53 | : | 7 | = | 7 | remainder ( 4 ) | ||||||||||||||
| 7 | : | 4 | = | 1 | remainder ( 3 ) | ||||||||||||||
| 4 | : | 3 | = | 1 | remainder ( 1 ) | ||||||||||||||
| 3 | : | 1 | = | 3 | remainder ( 0 ) | ||||||||||||||
| GCD = 1 | |||||||||||||||||||
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.