The GCD of given numbers is 3.
Step 1 :
Divide $ 567 $ by $ 411 $ and get the remainder
The remainder is positive ($ 156 > 0 $), so we will continue with division.
Step 2 :
Divide $ 411 $ by $ \color{blue}{ 156 } $ and get the remainder
The remainder is still positive ($ 99 > 0 $), so we will continue with division.
Step 3 :
Divide $ 156 $ by $ \color{blue}{ 99 } $ and get the remainder
The remainder is still positive ($ 57 > 0 $), so we will continue with division.
Step 4 :
Divide $ 99 $ by $ \color{blue}{ 57 } $ and get the remainder
The remainder is still positive ($ 42 > 0 $), so we will continue with division.
Step 5 :
Divide $ 57 $ by $ \color{blue}{ 42 } $ and get the remainder
The remainder is still positive ($ 15 > 0 $), so we will continue with division.
Step 6 :
Divide $ 42 $ by $ \color{blue}{ 15 } $ and get the remainder
The remainder is still positive ($ 12 > 0 $), so we will continue with division.
Step 7 :
Divide $ 15 $ by $ \color{blue}{ 12 } $ and get the remainder
The remainder is still positive ($ 3 > 0 $), so we will continue with division.
Step 8 :
Divide $ 12 $ by $ \color{blue}{ 3 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 3 }} $.
We can summarize an algorithm into a following table.
| 567 | : | 411 | = | 1 | remainder ( 156 ) | ||||||||||||||
| 411 | : | 156 | = | 2 | remainder ( 99 ) | ||||||||||||||
| 156 | : | 99 | = | 1 | remainder ( 57 ) | ||||||||||||||
| 99 | : | 57 | = | 1 | remainder ( 42 ) | ||||||||||||||
| 57 | : | 42 | = | 1 | remainder ( 15 ) | ||||||||||||||
| 42 | : | 15 | = | 2 | remainder ( 12 ) | ||||||||||||||
| 15 | : | 12 | = | 1 | remainder ( 3 ) | ||||||||||||||
| 12 | : | 3 | = | 4 | remainder ( 0 ) | ||||||||||||||
| GCD = 3 | |||||||||||||||||||
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.