The GCD of given numbers is 13.
Step 1 :
Divide $ 676 $ by $ 403 $ and get the remainder
The remainder is positive ($ 273 > 0 $), so we will continue with division.
Step 2 :
Divide $ 403 $ by $ \color{blue}{ 273 } $ and get the remainder
The remainder is still positive ($ 130 > 0 $), so we will continue with division.
Step 3 :
Divide $ 273 $ by $ \color{blue}{ 130 } $ and get the remainder
The remainder is still positive ($ 13 > 0 $), so we will continue with division.
Step 4 :
Divide $ 130 $ by $ \color{blue}{ 13 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 13 }} $.
We can summarize an algorithm into a following table.
| 676 | : | 403 | = | 1 | remainder ( 273 ) | ||||||
| 403 | : | 273 | = | 1 | remainder ( 130 ) | ||||||
| 273 | : | 130 | = | 2 | remainder ( 13 ) | ||||||
| 130 | : | 13 | = | 10 | remainder ( 0 ) | ||||||
| GCD = 13 | |||||||||||
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.