The GCD of given numbers is 1.
Step 1 :
Divide $ 12435648 $ by $ 37451 $ and get the remainder
The remainder is positive ($ 1916 > 0 $), so we will continue with division.
Step 2 :
Divide $ 37451 $ by $ \color{blue}{ 1916 } $ and get the remainder
The remainder is still positive ($ 1047 > 0 $), so we will continue with division.
Step 3 :
Divide $ 1916 $ by $ \color{blue}{ 1047 } $ and get the remainder
The remainder is still positive ($ 869 > 0 $), so we will continue with division.
Step 4 :
Divide $ 1047 $ by $ \color{blue}{ 869 } $ and get the remainder
The remainder is still positive ($ 178 > 0 $), so we will continue with division.
Step 5 :
Divide $ 869 $ by $ \color{blue}{ 178 } $ and get the remainder
The remainder is still positive ($ 157 > 0 $), so we will continue with division.
Step 6 :
Divide $ 178 $ by $ \color{blue}{ 157 } $ and get the remainder
The remainder is still positive ($ 21 > 0 $), so we will continue with division.
Step 7 :
Divide $ 157 $ by $ \color{blue}{ 21 } $ and get the remainder
The remainder is still positive ($ 10 > 0 $), so we will continue with division.
Step 8 :
Divide $ 21 $ by $ \color{blue}{ 10 } $ and get the remainder
The remainder is still positive ($ 1 > 0 $), so we will continue with division.
Step 9 :
Divide $ 10 $ by $ \color{blue}{ 1 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 1 }} $.
We can summarize an algorithm into a following table.
| 12435648 | : | 37451 | = | 332 | remainder ( 1916 ) | ||||||||||||||||
| 37451 | : | 1916 | = | 19 | remainder ( 1047 ) | ||||||||||||||||
| 1916 | : | 1047 | = | 1 | remainder ( 869 ) | ||||||||||||||||
| 1047 | : | 869 | = | 1 | remainder ( 178 ) | ||||||||||||||||
| 869 | : | 178 | = | 4 | remainder ( 157 ) | ||||||||||||||||
| 178 | : | 157 | = | 1 | remainder ( 21 ) | ||||||||||||||||
| 157 | : | 21 | = | 7 | remainder ( 10 ) | ||||||||||||||||
| 21 | : | 10 | = | 2 | remainder ( 1 ) | ||||||||||||||||
| 10 | : | 1 | = | 10 | remainder ( 0 ) | ||||||||||||||||
| GCD = 1 | |||||||||||||||||||||
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.