The GCD of given numbers is 51.
Step 1 :
Divide $ 3621 $ by $ 1938 $ and get the remainder
The remainder is positive ($ 1683 > 0 $), so we will continue with division.
Step 2 :
Divide $ 1938 $ by $ \color{blue}{ 1683 } $ and get the remainder
The remainder is still positive ($ 255 > 0 $), so we will continue with division.
Step 3 :
Divide $ 1683 $ by $ \color{blue}{ 255 } $ and get the remainder
The remainder is still positive ($ 153 > 0 $), so we will continue with division.
Step 4 :
Divide $ 255 $ by $ \color{blue}{ 153 } $ and get the remainder
The remainder is still positive ($ 102 > 0 $), so we will continue with division.
Step 5 :
Divide $ 153 $ by $ \color{blue}{ 102 } $ and get the remainder
The remainder is still positive ($ 51 > 0 $), so we will continue with division.
Step 6 :
Divide $ 102 $ by $ \color{blue}{ 51 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 51 }} $.
We can summarize an algorithm into a following table.
| 3621 | : | 1938 | = | 1 | remainder ( 1683 ) | ||||||||||
| 1938 | : | 1683 | = | 1 | remainder ( 255 ) | ||||||||||
| 1683 | : | 255 | = | 6 | remainder ( 153 ) | ||||||||||
| 255 | : | 153 | = | 1 | remainder ( 102 ) | ||||||||||
| 153 | : | 102 | = | 1 | remainder ( 51 ) | ||||||||||
| 102 | : | 51 | = | 2 | remainder ( 0 ) | ||||||||||
| GCD = 51 | |||||||||||||||
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.