Step 1 :
Divide $ 3210 $ by $ 1108 $ and get the remainder

$$ 3210 : 1108 = 2 \text{ ( remainder is } \color{blue}{ 994 } \text{ ) } $$

The remainder is positive ($ 994 > 0 $), so we will continue with division.

Step 2 :
Divide $ 1108 $ by $ \color{blue}{ 994 } $ and get the remainder

$$ 1108 : 994 = 1 \text{ ( remainder is } \color{blue}{ 114 } \text{ ) } $$

The remainder is still positive ($ 114 > 0 $), so we will continue with division.

Step 3 :
Divide $ 994 $ by $ \color{blue}{ 114 } $ and get the remainder

$$ 994 : 114 = 8 \text{ ( remainder is } \color{blue}{ 82 } \text{ ) } $$

The remainder is still positive ($ 82 > 0 $), so we will continue with division.

Step 4 :
Divide $ 114 $ by $ \color{blue}{ 82 } $ and get the remainder

$$ 114 : 82 = 1 \text{ ( remainder is } \color{blue}{ 32 } \text{ ) } $$

The remainder is still positive ($ 32 > 0 $), so we will continue with division.

Step 5 :
Divide $ 82 $ by $ \color{blue}{ 32 } $ and get the remainder

$$ 82 : 32 = 2 \text{ ( remainder is } \color{blue}{ 18 } \text{ ) } $$

The remainder is still positive ($ 18 > 0 $), so we will continue with division.

Step 6 :
Divide $ 32 $ by $ \color{blue}{ 18 } $ and get the remainder

$$ 32 : 18 = 1 \text{ ( remainder is } \color{blue}{ 14 } \text{ ) } $$

The remainder is still positive ($ 14 > 0 $), so we will continue with division.

Step 7 :
Divide $ 18 $ by $ \color{blue}{ 14 } $ and get the remainder

$$ 18 : 14 = 1 \text{ ( remainder is } \color{blue}{ 4 } \text{ ) } $$

The remainder is still positive ($ 4 > 0 $), so we will continue with division.

Step 8 :
Divide $ 14 $ by $ \color{blue}{ 4 } $ and get the remainder

$$ 14 : 4 = 3 \text{ ( remainder is } \color{blue}{ 2 } \text{ ) } $$

The remainder is still positive ($ 2 > 0 $), so we will continue with division.

Step 9 :
Divide $ 4 $ by $ \color{blue}{ 2 } $ and get the remainder

$$ 4 : \color{blue}{ \boxed { 2 }} = 2 \text{ ( remainder is } \color{blue}{ 0 } \text{ ) } $$

The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 2 }} $.

This solution can be visualized using a Venn diagram.

The GCD equals the product of the numbers at the intersection.

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