The GCD of given numbers is 1.
Step 1 :
Divide $ 3731 $ by $ 239 $ and get the remainder
The remainder is positive ($ 146 > 0 $), so we will continue with division.
Step 2 :
Divide $ 239 $ by $ \color{blue}{ 146 } $ and get the remainder
The remainder is still positive ($ 93 > 0 $), so we will continue with division.
Step 3 :
Divide $ 146 $ by $ \color{blue}{ 93 } $ and get the remainder
The remainder is still positive ($ 53 > 0 $), so we will continue with division.
Step 4 :
Divide $ 93 $ by $ \color{blue}{ 53 } $ and get the remainder
The remainder is still positive ($ 40 > 0 $), so we will continue with division.
Step 5 :
Divide $ 53 $ by $ \color{blue}{ 40 } $ and get the remainder
The remainder is still positive ($ 13 > 0 $), so we will continue with division.
Step 6 :
Divide $ 40 $ by $ \color{blue}{ 13 } $ and get the remainder
The remainder is still positive ($ 1 > 0 $), so we will continue with division.
Step 7 :
Divide $ 13 $ by $ \color{blue}{ 1 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 1 }} $.
We can summarize an algorithm into a following table.
| 3731 | : | 239 | = | 15 | remainder ( 146 ) | ||||||||||||
| 239 | : | 146 | = | 1 | remainder ( 93 ) | ||||||||||||
| 146 | : | 93 | = | 1 | remainder ( 53 ) | ||||||||||||
| 93 | : | 53 | = | 1 | remainder ( 40 ) | ||||||||||||
| 53 | : | 40 | = | 1 | remainder ( 13 ) | ||||||||||||
| 40 | : | 13 | = | 3 | remainder ( 1 ) | ||||||||||||
| 13 | : | 1 | = | 13 | remainder ( 0 ) | ||||||||||||
| GCD = 1 | |||||||||||||||||
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.