The GCD of given numbers is 13.
Step 1 :
Divide $ 2210 $ by $ 1131 $ and get the remainder
The remainder is positive ($ 1079 > 0 $), so we will continue with division.
Step 2 :
Divide $ 1131 $ by $ \color{blue}{ 1079 } $ and get the remainder
The remainder is still positive ($ 52 > 0 $), so we will continue with division.
Step 3 :
Divide $ 1079 $ by $ \color{blue}{ 52 } $ and get the remainder
The remainder is still positive ($ 39 > 0 $), so we will continue with division.
Step 4 :
Divide $ 52 $ by $ \color{blue}{ 39 } $ and get the remainder
The remainder is still positive ($ 13 > 0 $), so we will continue with division.
Step 5 :
Divide $ 39 $ by $ \color{blue}{ 13 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 13 }} $.
We can summarize an algorithm into a following table.
| 2210 | : | 1131 | = | 1 | remainder ( 1079 ) | ||||||||
| 1131 | : | 1079 | = | 1 | remainder ( 52 ) | ||||||||
| 1079 | : | 52 | = | 20 | remainder ( 39 ) | ||||||||
| 52 | : | 39 | = | 1 | remainder ( 13 ) | ||||||||
| 39 | : | 13 | = | 3 | remainder ( 0 ) | ||||||||
| GCD = 13 | |||||||||||||
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.