The GCD of given numbers is 7.
Step 1 :
Divide $ 2191 $ by $ 1351 $ and get the remainder
The remainder is positive ($ 840 > 0 $), so we will continue with division.
Step 2 :
Divide $ 1351 $ by $ \color{blue}{ 840 } $ and get the remainder
The remainder is still positive ($ 511 > 0 $), so we will continue with division.
Step 3 :
Divide $ 840 $ by $ \color{blue}{ 511 } $ and get the remainder
The remainder is still positive ($ 329 > 0 $), so we will continue with division.
Step 4 :
Divide $ 511 $ by $ \color{blue}{ 329 } $ and get the remainder
The remainder is still positive ($ 182 > 0 $), so we will continue with division.
Step 5 :
Divide $ 329 $ by $ \color{blue}{ 182 } $ and get the remainder
The remainder is still positive ($ 147 > 0 $), so we will continue with division.
Step 6 :
Divide $ 182 $ by $ \color{blue}{ 147 } $ and get the remainder
The remainder is still positive ($ 35 > 0 $), so we will continue with division.
Step 7 :
Divide $ 147 $ by $ \color{blue}{ 35 } $ and get the remainder
The remainder is still positive ($ 7 > 0 $), so we will continue with division.
Step 8 :
Divide $ 35 $ by $ \color{blue}{ 7 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 7 }} $.
We can summarize an algorithm into a following table.
| 2191 | : | 1351 | = | 1 | remainder ( 840 ) | ||||||||||||||
| 1351 | : | 840 | = | 1 | remainder ( 511 ) | ||||||||||||||
| 840 | : | 511 | = | 1 | remainder ( 329 ) | ||||||||||||||
| 511 | : | 329 | = | 1 | remainder ( 182 ) | ||||||||||||||
| 329 | : | 182 | = | 1 | remainder ( 147 ) | ||||||||||||||
| 182 | : | 147 | = | 1 | remainder ( 35 ) | ||||||||||||||
| 147 | : | 35 | = | 4 | remainder ( 7 ) | ||||||||||||||
| 35 | : | 7 | = | 5 | remainder ( 0 ) | ||||||||||||||
| GCD = 7 | |||||||||||||||||||
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.