The GCD of given numbers is 50.
Step 1 :
Divide $ 19950 $ by $ 14950 $ and get the remainder
The remainder is positive ($ 5000 > 0 $), so we will continue with division.
Step 2 :
Divide $ 14950 $ by $ \color{blue}{ 5000 } $ and get the remainder
The remainder is still positive ($ 4950 > 0 $), so we will continue with division.
Step 3 :
Divide $ 5000 $ by $ \color{blue}{ 4950 } $ and get the remainder
The remainder is still positive ($ 50 > 0 $), so we will continue with division.
Step 4 :
Divide $ 4950 $ by $ \color{blue}{ 50 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 50 }} $.
We can summarize an algorithm into a following table.
| 19950 | : | 14950 | = | 1 | remainder ( 5000 ) | ||||||
| 14950 | : | 5000 | = | 2 | remainder ( 4950 ) | ||||||
| 5000 | : | 4950 | = | 1 | remainder ( 50 ) | ||||||
| 4950 | : | 50 | = | 99 | remainder ( 0 ) | ||||||
| GCD = 50 | |||||||||||
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.