The GCD of given numbers is 1.
Step 1 :
Divide $ 1870 $ by $ 261 $ and get the remainder
The remainder is positive ($ 43 > 0 $), so we will continue with division.
Step 2 :
Divide $ 261 $ by $ \color{blue}{ 43 } $ and get the remainder
The remainder is still positive ($ 3 > 0 $), so we will continue with division.
Step 3 :
Divide $ 43 $ by $ \color{blue}{ 3 } $ and get the remainder
The remainder is still positive ($ 1 > 0 $), so we will continue with division.
Step 4 :
Divide $ 3 $ by $ \color{blue}{ 1 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 1 }} $.
We can summarize an algorithm into a following table.
| 1870 | : | 261 | = | 7 | remainder ( 43 ) | ||||||
| 261 | : | 43 | = | 6 | remainder ( 3 ) | ||||||
| 43 | : | 3 | = | 14 | remainder ( 1 ) | ||||||
| 3 | : | 1 | = | 3 | remainder ( 0 ) | ||||||
| GCD = 1 | |||||||||||
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.