The GCD of given numbers is 1.
Step 1 :
Divide $ 24601 $ by $ 1776 $ and get the remainder
The remainder is positive ($ 1513 > 0 $), so we will continue with division.
Step 2 :
Divide $ 1776 $ by $ \color{blue}{ 1513 } $ and get the remainder
The remainder is still positive ($ 263 > 0 $), so we will continue with division.
Step 3 :
Divide $ 1513 $ by $ \color{blue}{ 263 } $ and get the remainder
The remainder is still positive ($ 198 > 0 $), so we will continue with division.
Step 4 :
Divide $ 263 $ by $ \color{blue}{ 198 } $ and get the remainder
The remainder is still positive ($ 65 > 0 $), so we will continue with division.
Step 5 :
Divide $ 198 $ by $ \color{blue}{ 65 } $ and get the remainder
The remainder is still positive ($ 3 > 0 $), so we will continue with division.
Step 6 :
Divide $ 65 $ by $ \color{blue}{ 3 } $ and get the remainder
The remainder is still positive ($ 2 > 0 $), so we will continue with division.
Step 7 :
Divide $ 3 $ by $ \color{blue}{ 2 } $ and get the remainder
The remainder is still positive ($ 1 > 0 $), so we will continue with division.
Step 8 :
Divide $ 2 $ by $ \color{blue}{ 1 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 1 }} $.
We can summarize an algorithm into a following table.
| 24601 | : | 1776 | = | 13 | remainder ( 1513 ) | ||||||||||||||
| 1776 | : | 1513 | = | 1 | remainder ( 263 ) | ||||||||||||||
| 1513 | : | 263 | = | 5 | remainder ( 198 ) | ||||||||||||||
| 263 | : | 198 | = | 1 | remainder ( 65 ) | ||||||||||||||
| 198 | : | 65 | = | 3 | remainder ( 3 ) | ||||||||||||||
| 65 | : | 3 | = | 21 | remainder ( 2 ) | ||||||||||||||
| 3 | : | 2 | = | 1 | remainder ( 1 ) | ||||||||||||||
| 2 | : | 1 | = | 2 | remainder ( 0 ) | ||||||||||||||
| GCD = 1 | |||||||||||||||||||
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.