The GCD of given numbers is 10.
Step 1 :
Divide $ 17610 $ by $ 12610 $ and get the remainder
The remainder is positive ($ 5000 > 0 $), so we will continue with division.
Step 2 :
Divide $ 12610 $ by $ \color{blue}{ 5000 } $ and get the remainder
The remainder is still positive ($ 2610 > 0 $), so we will continue with division.
Step 3 :
Divide $ 5000 $ by $ \color{blue}{ 2610 } $ and get the remainder
The remainder is still positive ($ 2390 > 0 $), so we will continue with division.
Step 4 :
Divide $ 2610 $ by $ \color{blue}{ 2390 } $ and get the remainder
The remainder is still positive ($ 220 > 0 $), so we will continue with division.
Step 5 :
Divide $ 2390 $ by $ \color{blue}{ 220 } $ and get the remainder
The remainder is still positive ($ 190 > 0 $), so we will continue with division.
Step 6 :
Divide $ 220 $ by $ \color{blue}{ 190 } $ and get the remainder
The remainder is still positive ($ 30 > 0 $), so we will continue with division.
Step 7 :
Divide $ 190 $ by $ \color{blue}{ 30 } $ and get the remainder
The remainder is still positive ($ 10 > 0 $), so we will continue with division.
Step 8 :
Divide $ 30 $ by $ \color{blue}{ 10 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 10 }} $.
We can summarize an algorithm into a following table.
| 17610 | : | 12610 | = | 1 | remainder ( 5000 ) | ||||||||||||||
| 12610 | : | 5000 | = | 2 | remainder ( 2610 ) | ||||||||||||||
| 5000 | : | 2610 | = | 1 | remainder ( 2390 ) | ||||||||||||||
| 2610 | : | 2390 | = | 1 | remainder ( 220 ) | ||||||||||||||
| 2390 | : | 220 | = | 10 | remainder ( 190 ) | ||||||||||||||
| 220 | : | 190 | = | 1 | remainder ( 30 ) | ||||||||||||||
| 190 | : | 30 | = | 6 | remainder ( 10 ) | ||||||||||||||
| 30 | : | 10 | = | 3 | remainder ( 0 ) | ||||||||||||||
| GCD = 10 | |||||||||||||||||||
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.