The GCD of given numbers is 10.
Step 1 :
Divide $ 16390 $ by $ 11390 $ and get the remainder
The remainder is positive ($ 5000 > 0 $), so we will continue with division.
Step 2 :
Divide $ 11390 $ by $ \color{blue}{ 5000 } $ and get the remainder
The remainder is still positive ($ 1390 > 0 $), so we will continue with division.
Step 3 :
Divide $ 5000 $ by $ \color{blue}{ 1390 } $ and get the remainder
The remainder is still positive ($ 830 > 0 $), so we will continue with division.
Step 4 :
Divide $ 1390 $ by $ \color{blue}{ 830 } $ and get the remainder
The remainder is still positive ($ 560 > 0 $), so we will continue with division.
Step 5 :
Divide $ 830 $ by $ \color{blue}{ 560 } $ and get the remainder
The remainder is still positive ($ 270 > 0 $), so we will continue with division.
Step 6 :
Divide $ 560 $ by $ \color{blue}{ 270 } $ and get the remainder
The remainder is still positive ($ 20 > 0 $), so we will continue with division.
Step 7 :
Divide $ 270 $ by $ \color{blue}{ 20 } $ and get the remainder
The remainder is still positive ($ 10 > 0 $), so we will continue with division.
Step 8 :
Divide $ 20 $ by $ \color{blue}{ 10 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 10 }} $.
We can summarize an algorithm into a following table.
| 16390 | : | 11390 | = | 1 | remainder ( 5000 ) | ||||||||||||||
| 11390 | : | 5000 | = | 2 | remainder ( 1390 ) | ||||||||||||||
| 5000 | : | 1390 | = | 3 | remainder ( 830 ) | ||||||||||||||
| 1390 | : | 830 | = | 1 | remainder ( 560 ) | ||||||||||||||
| 830 | : | 560 | = | 1 | remainder ( 270 ) | ||||||||||||||
| 560 | : | 270 | = | 2 | remainder ( 20 ) | ||||||||||||||
| 270 | : | 20 | = | 13 | remainder ( 10 ) | ||||||||||||||
| 20 | : | 10 | = | 2 | remainder ( 0 ) | ||||||||||||||
| GCD = 10 | |||||||||||||||||||
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.