The GCD of given numbers is 10.
Step 1 :
Divide $ 16170 $ by $ 11170 $ and get the remainder
The remainder is positive ($ 5000 > 0 $), so we will continue with division.
Step 2 :
Divide $ 11170 $ by $ \color{blue}{ 5000 } $ and get the remainder
The remainder is still positive ($ 1170 > 0 $), so we will continue with division.
Step 3 :
Divide $ 5000 $ by $ \color{blue}{ 1170 } $ and get the remainder
The remainder is still positive ($ 320 > 0 $), so we will continue with division.
Step 4 :
Divide $ 1170 $ by $ \color{blue}{ 320 } $ and get the remainder
The remainder is still positive ($ 210 > 0 $), so we will continue with division.
Step 5 :
Divide $ 320 $ by $ \color{blue}{ 210 } $ and get the remainder
The remainder is still positive ($ 110 > 0 $), so we will continue with division.
Step 6 :
Divide $ 210 $ by $ \color{blue}{ 110 } $ and get the remainder
The remainder is still positive ($ 100 > 0 $), so we will continue with division.
Step 7 :
Divide $ 110 $ by $ \color{blue}{ 100 } $ and get the remainder
The remainder is still positive ($ 10 > 0 $), so we will continue with division.
Step 8 :
Divide $ 100 $ by $ \color{blue}{ 10 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 10 }} $.
We can summarize an algorithm into a following table.
| 16170 | : | 11170 | = | 1 | remainder ( 5000 ) | ||||||||||||||
| 11170 | : | 5000 | = | 2 | remainder ( 1170 ) | ||||||||||||||
| 5000 | : | 1170 | = | 4 | remainder ( 320 ) | ||||||||||||||
| 1170 | : | 320 | = | 3 | remainder ( 210 ) | ||||||||||||||
| 320 | : | 210 | = | 1 | remainder ( 110 ) | ||||||||||||||
| 210 | : | 110 | = | 1 | remainder ( 100 ) | ||||||||||||||
| 110 | : | 100 | = | 1 | remainder ( 10 ) | ||||||||||||||
| 100 | : | 10 | = | 10 | remainder ( 0 ) | ||||||||||||||
| GCD = 10 | |||||||||||||||||||
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.