The GCD of given numbers is 10.
Step 1 :
Divide $ 16110 $ by $ 11110 $ and get the remainder
The remainder is positive ($ 5000 > 0 $), so we will continue with division.
Step 2 :
Divide $ 11110 $ by $ \color{blue}{ 5000 } $ and get the remainder
The remainder is still positive ($ 1110 > 0 $), so we will continue with division.
Step 3 :
Divide $ 5000 $ by $ \color{blue}{ 1110 } $ and get the remainder
The remainder is still positive ($ 560 > 0 $), so we will continue with division.
Step 4 :
Divide $ 1110 $ by $ \color{blue}{ 560 } $ and get the remainder
The remainder is still positive ($ 550 > 0 $), so we will continue with division.
Step 5 :
Divide $ 560 $ by $ \color{blue}{ 550 } $ and get the remainder
The remainder is still positive ($ 10 > 0 $), so we will continue with division.
Step 6 :
Divide $ 550 $ by $ \color{blue}{ 10 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 10 }} $.
We can summarize an algorithm into a following table.
| 16110 | : | 11110 | = | 1 | remainder ( 5000 ) | ||||||||||
| 11110 | : | 5000 | = | 2 | remainder ( 1110 ) | ||||||||||
| 5000 | : | 1110 | = | 4 | remainder ( 560 ) | ||||||||||
| 1110 | : | 560 | = | 1 | remainder ( 550 ) | ||||||||||
| 560 | : | 550 | = | 1 | remainder ( 10 ) | ||||||||||
| 550 | : | 10 | = | 55 | remainder ( 0 ) | ||||||||||
| GCD = 10 | |||||||||||||||
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.