The GCD of given numbers is 10.
Step 1 :
Divide $ 15610 $ by $ 10610 $ and get the remainder
The remainder is positive ($ 5000 > 0 $), so we will continue with division.
Step 2 :
Divide $ 10610 $ by $ \color{blue}{ 5000 } $ and get the remainder
The remainder is still positive ($ 610 > 0 $), so we will continue with division.
Step 3 :
Divide $ 5000 $ by $ \color{blue}{ 610 } $ and get the remainder
The remainder is still positive ($ 120 > 0 $), so we will continue with division.
Step 4 :
Divide $ 610 $ by $ \color{blue}{ 120 } $ and get the remainder
The remainder is still positive ($ 10 > 0 $), so we will continue with division.
Step 5 :
Divide $ 120 $ by $ \color{blue}{ 10 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 10 }} $.
We can summarize an algorithm into a following table.
| 15610 | : | 10610 | = | 1 | remainder ( 5000 ) | ||||||||
| 10610 | : | 5000 | = | 2 | remainder ( 610 ) | ||||||||
| 5000 | : | 610 | = | 8 | remainder ( 120 ) | ||||||||
| 610 | : | 120 | = | 5 | remainder ( 10 ) | ||||||||
| 120 | : | 10 | = | 12 | remainder ( 0 ) | ||||||||
| GCD = 10 | |||||||||||||
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.