The GCD of given numbers is 4.
Step 1 :
Divide $ 1468 $ by $ 40 $ and get the remainder
The remainder is positive ($ 28 > 0 $), so we will continue with division.
Step 2 :
Divide $ 40 $ by $ \color{blue}{ 28 } $ and get the remainder
The remainder is still positive ($ 12 > 0 $), so we will continue with division.
Step 3 :
Divide $ 28 $ by $ \color{blue}{ 12 } $ and get the remainder
The remainder is still positive ($ 4 > 0 $), so we will continue with division.
Step 4 :
Divide $ 12 $ by $ \color{blue}{ 4 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 4 }} $.
We can summarize an algorithm into a following table.
| 1468 | : | 40 | = | 36 | remainder ( 28 ) | ||||||
| 40 | : | 28 | = | 1 | remainder ( 12 ) | ||||||
| 28 | : | 12 | = | 2 | remainder ( 4 ) | ||||||
| 12 | : | 4 | = | 3 | remainder ( 0 ) | ||||||
| GCD = 4 | |||||||||||
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.