The GCD of given numbers is 1.
Step 1 :
Divide $ 1203 $ by $ 460 $ and get the remainder
The remainder is positive ($ 283 > 0 $), so we will continue with division.
Step 2 :
Divide $ 460 $ by $ \color{blue}{ 283 } $ and get the remainder
The remainder is still positive ($ 177 > 0 $), so we will continue with division.
Step 3 :
Divide $ 283 $ by $ \color{blue}{ 177 } $ and get the remainder
The remainder is still positive ($ 106 > 0 $), so we will continue with division.
Step 4 :
Divide $ 177 $ by $ \color{blue}{ 106 } $ and get the remainder
The remainder is still positive ($ 71 > 0 $), so we will continue with division.
Step 5 :
Divide $ 106 $ by $ \color{blue}{ 71 } $ and get the remainder
The remainder is still positive ($ 35 > 0 $), so we will continue with division.
Step 6 :
Divide $ 71 $ by $ \color{blue}{ 35 } $ and get the remainder
The remainder is still positive ($ 1 > 0 $), so we will continue with division.
Step 7 :
Divide $ 35 $ by $ \color{blue}{ 1 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 1 }} $.
We can summarize an algorithm into a following table.
| 1203 | : | 460 | = | 2 | remainder ( 283 ) | ||||||||||||
| 460 | : | 283 | = | 1 | remainder ( 177 ) | ||||||||||||
| 283 | : | 177 | = | 1 | remainder ( 106 ) | ||||||||||||
| 177 | : | 106 | = | 1 | remainder ( 71 ) | ||||||||||||
| 106 | : | 71 | = | 1 | remainder ( 35 ) | ||||||||||||
| 71 | : | 35 | = | 2 | remainder ( 1 ) | ||||||||||||
| 35 | : | 1 | = | 35 | remainder ( 0 ) | ||||||||||||
| GCD = 1 | |||||||||||||||||
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.