The GCD of given numbers is 3.
Step 1 :
Divide $ 1149 $ by $ 201 $ and get the remainder
The remainder is positive ($ 144 > 0 $), so we will continue with division.
Step 2 :
Divide $ 201 $ by $ \color{blue}{ 144 } $ and get the remainder
The remainder is still positive ($ 57 > 0 $), so we will continue with division.
Step 3 :
Divide $ 144 $ by $ \color{blue}{ 57 } $ and get the remainder
The remainder is still positive ($ 30 > 0 $), so we will continue with division.
Step 4 :
Divide $ 57 $ by $ \color{blue}{ 30 } $ and get the remainder
The remainder is still positive ($ 27 > 0 $), so we will continue with division.
Step 5 :
Divide $ 30 $ by $ \color{blue}{ 27 } $ and get the remainder
The remainder is still positive ($ 3 > 0 $), so we will continue with division.
Step 6 :
Divide $ 27 $ by $ \color{blue}{ 3 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 3 }} $.
We can summarize an algorithm into a following table.
| 1149 | : | 201 | = | 5 | remainder ( 144 ) | ||||||||||
| 201 | : | 144 | = | 1 | remainder ( 57 ) | ||||||||||
| 144 | : | 57 | = | 2 | remainder ( 30 ) | ||||||||||
| 57 | : | 30 | = | 1 | remainder ( 27 ) | ||||||||||
| 30 | : | 27 | = | 1 | remainder ( 3 ) | ||||||||||
| 27 | : | 3 | = | 9 | remainder ( 0 ) | ||||||||||
| GCD = 3 | |||||||||||||||
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.