The GCD of given numbers is 2.
Step 1 :
Divide $ 108 $ by $ 10 $ and get the remainder
The remainder is positive ($ 8 > 0 $), so we will continue with division.
Step 2 :
Divide $ 10 $ by $ \color{blue}{ 8 } $ and get the remainder
The remainder is still positive ($ 2 > 0 $), so we will continue with division.
Step 3 :
Divide $ 8 $ by $ \color{blue}{ 2 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 2 }} $.
We can summarize an algorithm into a following table.
| 108 | : | 10 | = | 10 | remainder ( 8 ) | ||||
| 10 | : | 8 | = | 1 | remainder ( 2 ) | ||||
| 8 | : | 2 | = | 4 | remainder ( 0 ) | ||||
| GCD = 2 | |||||||||
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.