The GCD of given numbers is 1.
Step 1 :
Divide $ 1021763679 $ by $ 519424709 $ and get the remainder
The remainder is positive ($ 502338970 > 0 $), so we will continue with division.
Step 2 :
Divide $ 519424709 $ by $ \color{blue}{ 502338970 } $ and get the remainder
The remainder is still positive ($ 17085739 > 0 $), so we will continue with division.
Step 3 :
Divide $ 502338970 $ by $ \color{blue}{ 17085739 } $ and get the remainder
The remainder is still positive ($ 6852539 > 0 $), so we will continue with division.
Step 4 :
Divide $ 17085739 $ by $ \color{blue}{ 6852539 } $ and get the remainder
The remainder is still positive ($ 3380661 > 0 $), so we will continue with division.
Step 5 :
Divide $ 6852539 $ by $ \color{blue}{ 3380661 } $ and get the remainder
The remainder is still positive ($ 91217 > 0 $), so we will continue with division.
Step 6 :
Divide $ 3380661 $ by $ \color{blue}{ 91217 } $ and get the remainder
The remainder is still positive ($ 5632 > 0 $), so we will continue with division.
Step 7 :
Divide $ 91217 $ by $ \color{blue}{ 5632 } $ and get the remainder
The remainder is still positive ($ 1105 > 0 $), so we will continue with division.
Step 8 :
Divide $ 5632 $ by $ \color{blue}{ 1105 } $ and get the remainder
The remainder is still positive ($ 107 > 0 $), so we will continue with division.
Step 9 :
Divide $ 1105 $ by $ \color{blue}{ 107 } $ and get the remainder
The remainder is still positive ($ 35 > 0 $), so we will continue with division.
Step 10 :
Divide $ 107 $ by $ \color{blue}{ 35 } $ and get the remainder
The remainder is still positive ($ 2 > 0 $), so we will continue with division.
Step 11 :
Divide $ 35 $ by $ \color{blue}{ 2 } $ and get the remainder
The remainder is still positive ($ 1 > 0 $), so we will continue with division.
Step 12 :
Divide $ 2 $ by $ \color{blue}{ 1 } $ and get the remainder
The remainder is zero => GCD is the last divisor $ \color{blue}{ \boxed { 1 }} $.
We can summarize an algorithm into a following table.
| 1021763679 | : | 519424709 | = | 1 | remainder ( 502338970 ) | ||||||||||||||||||||||
| 519424709 | : | 502338970 | = | 1 | remainder ( 17085739 ) | ||||||||||||||||||||||
| 502338970 | : | 17085739 | = | 29 | remainder ( 6852539 ) | ||||||||||||||||||||||
| 17085739 | : | 6852539 | = | 2 | remainder ( 3380661 ) | ||||||||||||||||||||||
| 6852539 | : | 3380661 | = | 2 | remainder ( 91217 ) | ||||||||||||||||||||||
| 3380661 | : | 91217 | = | 37 | remainder ( 5632 ) | ||||||||||||||||||||||
| 91217 | : | 5632 | = | 16 | remainder ( 1105 ) | ||||||||||||||||||||||
| 5632 | : | 1105 | = | 5 | remainder ( 107 ) | ||||||||||||||||||||||
| 1105 | : | 107 | = | 10 | remainder ( 35 ) | ||||||||||||||||||||||
| 107 | : | 35 | = | 3 | remainder ( 2 ) | ||||||||||||||||||||||
| 35 | : | 2 | = | 17 | remainder ( 1 ) | ||||||||||||||||||||||
| 2 | : | 1 | = | 2 | remainder ( 0 ) | ||||||||||||||||||||||
| GCD = 1 | |||||||||||||||||||||||||||
This solution can be visualized using a Venn diagram.
The GCD equals the product of the numbers at the intersection.