The following calculator will find standard deviation, variance, skewness and kurtosis of the given data set. The calculator will generate a step by step explanation on how to find these values.
solution
You entered the following data set:
$$\begin{array}{cccc}5.14&5.15&5.17&5.20\\5.20&5.18&5.15&5.15\\5.16&5.16&&\end{array} $$The standard deviation of the data set is:
$$ \sigma = 0.02 $$explanation
To find standard deviation we use the following formula
$$ \sigma = \sqrt{ \frac{ \sum{\left(x_i - \overline{X}\right)^2 }}{n} } $$We will compute this formula in 4 steps.
Step 1: Find the mean. $ \left( \overline{X} \right)$
In this example: $ \overline{X} = 5.166 $. (use this calculator for step by step explanation on how to find mean).
Step 2: Create the following table.
data | data-mean | (data - mean)2 |
5.14 | -0.026000000000001 | 0.00067600000000004 |
5.15 | -0.016 | 0.000256 |
5.17 | 0.0039999999999996 | 1.5999999999996E-5 |
5.20 | 0.034 | 0.001156 |
5.20 | 0.034 | 0.001156 |
5.18 | 0.013999999999999 | 0.00019599999999998 |
5.15 | -0.016 | 0.000256 |
5.15 | -0.016 | 0.000256 |
5.16 | -0.0060000000000002 | 3.6000000000003E-5 |
5.16 | -0.0060000000000002 | 3.6000000000003E-5 |
Step 3: Find the sum of numbers in the last column to get.
$$ \sum{\left(x_i - \overline{X}\right)^2} = 0.004 $$Step 4: Calculate $ \sigma $ using the above formula.
$$ \sigma = \sqrt{ \frac{ \sum{\left(x_i - \overline{X}\right)^2 }}{n} } = \sqrt{ \frac{ 0.004 }{ 10} } \approx 0.02$$Definition: The standard deviation measures how close the set of data is to the mean value of the data set. If data set have high standard deviation than the values are spread out very much. If data set have small standard deviation the data points are very close to the mean.
Please tell me how can I make this better.