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• Tests on solving radical equations and inequalities

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•  Question 1: 1 pts Which of these is radical equation?
 $x + \sqrt{2} = 3$ $x + 2 = \sqrt{3}$ $\sqrt{x} + 2 = 3$
•  Question 2: 1 pts Which of these is not a radical equation?
 $\sqrt{x+1} = \sqrt{x+1}$ $x + 2 = \sqrt{x}$ $x + \sqrt{2} = \sqrt{23}$
•  Question 3: 1 pts Find the solution $\sqrt{x^2} = \sqrt{x}$
 $x = 2$ $x = -2$ $x = 0$ $x = 0 \, or \, x = 2$
•  Question 4: 1 pts The equation $\sqrt{-x} = 2$ has no soultions.
•  Question 5: 2 pts Which equation does not have a solution?
 $-\sqrt{x} = -2$ $\sqrt{x} = 2$ $-\sqrt{-x} = -2$ $\sqrt{-x} = -2$
•  Question 6: 2 pts Which equation does not have a solution?
 $\sqrt{x} = \sqrt{-x}$ $-\sqrt{x} = \sqrt{-x}$ $\sqrt{1-x} = \sqrt{x-1}$ $\sqrt{1+x} = \sqrt{x-1}$
•  Question 7: 2 pts What is the solution of $\sqrt{x-1}-1=-1$?
 $0$ $1$ $2$ $3$
•  Question 8: 2 pts What is the solution of $\sqrt{x+2}+4=7$
 $-7$ $7$ $3$ $-3$
•  Question 9: 3 pts What is the solution of $\sqrt{x-12}-\sqrt{x} = -2$
 $12$ $16$ $-12$ $-16$
•  Question 10: 3 pts What is the solution of $\sqrt{x+7} = 2\sqrt{2}$
 $1$ $2$ $3$ $4$
•  Question 11: 3 pts What is the solution of $\sqrt{x^2-4x+9} = x-1$
 $1$ $2$ $3$ $4$