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Tests on rationalizing denominator
Rationalizing denominator with with one radical term
Rationalizing denominator with with one radical term
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Question 1:
1 pts
Is the following computation correct? $$\frac{1}{\sqrt{2}} = \frac{1}{\sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{2}} {4}$$
this is correct
this is not correct
Question 2:
1 pts
What number we need to put instead ? to rationalize the denominator in: $$ \frac{1}{\sqrt{5}} = \frac{1}{\sqrt{5}}\cdot\frac{?}{?}$$
$? = \sqrt{15}$
$? = \sqrt{5}$
$? = \sqrt{25}$
Question 3:
1 pts
Rewrite $\frac{1}{\sqrt{3}}$ by rationalizing the denominator.
$\frac{3}{\sqrt{3}}$
$3$
$\sqrt{3}$
$\frac{\sqrt{3}}{3}$
Question 4:
1 pts
Rationalize the denominator $\frac{14}{\sqrt{7}}$
$\frac{14}{7\sqrt{7}}$
$2\sqrt{7}$
$14\sqrt{7}$
Question 5:
2 pts
Rationalize the denominator $$\sqrt{\frac{4}{5}}$$
$\frac{2}{\sqrt{5}}$
$2\sqrt{5}$
$\frac{2\sqrt{5}}{5}$
Question 6:
2 pts
Simplify $$\frac{1}{\sqrt{12}}$$
$\frac{\sqrt{3}}{6}$
$\frac{\sqrt{12}}{12}$
$12\sqrt{3}$
Question 7:
2 pts
Rationalize the denominator $$\sqrt{\frac{3}{6}}$$
$\frac{\sqrt{18}}{6}$
$\frac{3\sqrt{6}}{6}$
$\frac{\sqrt{2}}{2}$
Question 8:
3 pts
Rationalize the denominator $$\frac{1}{\sqrt{x}}$$
$\frac{\sqrt{x}}{x}$
$\sqrt{x}$
$x\sqrt{x}$
Question 9:
3 pts
Rationalize the denominator $$\frac{24}{\sqrt{3x}}$$
$8\sqrt{3x}$
$\frac{24\sqrt{3x}}{3x}$
$\frac{8\sqrt{3x}}{x}$
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