To find area $ A $ use formula:

$$ A = \frac{ a^2 \sqrt{3}}{2} + 3 a l $$

After substituting $a = 6\, \text{cm}$ and $l = 4\, \text{cm}$ we have:

$$ A = \frac{ 6\, \text{cm}^2 \sqrt{3}}{2} + 3 \cdot 6\, \text{cm} \cdot 4\, \text{cm} $$$$ A = \frac{ 36\, \text{cm}^2 \sqrt{3}}{2} + 3 \cdot 24\, \text{cm}^2 $$$$ A = \frac{ 36 \sqrt{ 3 }\, \text{cm}^2}{2} + 72\, \text{cm}^2 $$$$ A = 18 \sqrt{ 3 }\, \text{cm}^2 + 72\, \text{cm}^2 $$$$ A = 103.1769\, \text{cm}^2 $$

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