Divide using synthetic division $$ ( x^{3}+4x^{2}-3x-6 ) \div ( x+2 ) $$
The synthetic division table is:
$$ \begin{array}{c|rrrr}-2&1&4&-3&-6\\& & -2& -4& \color{black}{14} \\ \hline &\color{blue}{1}&\color{blue}{2}&\color{blue}{-7}&\color{orangered}{8} \end{array} $$The solution is:
$$ \dfrac{ x^{3}+4x^{2}-3x-6 }{ x+2 } = \color{blue}{x^{2}+2x-7} ~+~ \dfrac{ \color{red}{ 8 } }{ x+2 } $$Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x + 2 = 0 $ ( $ x = \color{blue}{ -2 } $ ) at the left.
$$ \begin{array}{c|rrrr}\color{blue}{-2}&1&4&-3&-6\\& & & & \\ \hline &&&& \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rrrr}-2&\color{orangered}{ 1 }&4&-3&-6\\& & & & \\ \hline &\color{orangered}{1}&&& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ -2 } \cdot \color{blue}{ 1 } = \color{blue}{ -2 } $.
$$ \begin{array}{c|rrrr}\color{blue}{-2}&1&4&-3&-6\\& & \color{blue}{-2} & & \\ \hline &\color{blue}{1}&&& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ 4 } + \color{orangered}{ \left( -2 \right) } = \color{orangered}{ 2 } $
$$ \begin{array}{c|rrrr}-2&1&\color{orangered}{ 4 }&-3&-6\\& & \color{orangered}{-2} & & \\ \hline &1&\color{orangered}{2}&& \end{array} $$Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ -2 } \cdot \color{blue}{ 2 } = \color{blue}{ -4 } $.
$$ \begin{array}{c|rrrr}\color{blue}{-2}&1&4&-3&-6\\& & -2& \color{blue}{-4} & \\ \hline &1&\color{blue}{2}&& \end{array} $$Step 5 : Add down last column: $ \color{orangered}{ -3 } + \color{orangered}{ \left( -4 \right) } = \color{orangered}{ -7 } $
$$ \begin{array}{c|rrrr}-2&1&4&\color{orangered}{ -3 }&-6\\& & -2& \color{orangered}{-4} & \\ \hline &1&2&\color{orangered}{-7}& \end{array} $$Step 6 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ -2 } \cdot \color{blue}{ \left( -7 \right) } = \color{blue}{ 14 } $.
$$ \begin{array}{c|rrrr}\color{blue}{-2}&1&4&-3&-6\\& & -2& -4& \color{blue}{14} \\ \hline &1&2&\color{blue}{-7}& \end{array} $$Step 7 : Add down last column: $ \color{orangered}{ -6 } + \color{orangered}{ 14 } = \color{orangered}{ 8 } $
$$ \begin{array}{c|rrrr}-2&1&4&-3&\color{orangered}{ -6 }\\& & -2& -4& \color{orangered}{14} \\ \hline &\color{blue}{1}&\color{blue}{2}&\color{blue}{-7}&\color{orangered}{8} \end{array} $$Bottom line represents the quotient $ \color{blue}{ x^{2}+2x-7 } $ with a remainder of $ \color{red}{ 8 } $.