Divide using synthetic division $$ ( 3x^{3}-4x^{2}-48x+64 ) \div ( x+4 ) $$
The synthetic division table is:
$$ \begin{array}{c|rrrr}-4&3&-4&-48&64\\& & -12& 64& \color{black}{-64} \\ \hline &\color{blue}{3}&\color{blue}{-16}&\color{blue}{16}&\color{orangered}{0} \end{array} $$The solution is:
$$ \dfrac{ 3x^{3}-4x^{2}-48x+64 }{ x+4 } = \color{blue}{3x^{2}-16x+16} $$Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x + 4 = 0 $ ( $ x = \color{blue}{ -4 } $ ) at the left.
$$ \begin{array}{c|rrrr}\color{blue}{-4}&3&-4&-48&64\\& & & & \\ \hline &&&& \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rrrr}-4&\color{orangered}{ 3 }&-4&-48&64\\& & & & \\ \hline &\color{orangered}{3}&&& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ -4 } \cdot \color{blue}{ 3 } = \color{blue}{ -12 } $.
$$ \begin{array}{c|rrrr}\color{blue}{-4}&3&-4&-48&64\\& & \color{blue}{-12} & & \\ \hline &\color{blue}{3}&&& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ -4 } + \color{orangered}{ \left( -12 \right) } = \color{orangered}{ -16 } $
$$ \begin{array}{c|rrrr}-4&3&\color{orangered}{ -4 }&-48&64\\& & \color{orangered}{-12} & & \\ \hline &3&\color{orangered}{-16}&& \end{array} $$Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ -4 } \cdot \color{blue}{ \left( -16 \right) } = \color{blue}{ 64 } $.
$$ \begin{array}{c|rrrr}\color{blue}{-4}&3&-4&-48&64\\& & -12& \color{blue}{64} & \\ \hline &3&\color{blue}{-16}&& \end{array} $$Step 5 : Add down last column: $ \color{orangered}{ -48 } + \color{orangered}{ 64 } = \color{orangered}{ 16 } $
$$ \begin{array}{c|rrrr}-4&3&-4&\color{orangered}{ -48 }&64\\& & -12& \color{orangered}{64} & \\ \hline &3&-16&\color{orangered}{16}& \end{array} $$Step 6 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ -4 } \cdot \color{blue}{ 16 } = \color{blue}{ -64 } $.
$$ \begin{array}{c|rrrr}\color{blue}{-4}&3&-4&-48&64\\& & -12& 64& \color{blue}{-64} \\ \hline &3&-16&\color{blue}{16}& \end{array} $$Step 7 : Add down last column: $ \color{orangered}{ 64 } + \color{orangered}{ \left( -64 \right) } = \color{orangered}{ 0 } $
$$ \begin{array}{c|rrrr}-4&3&-4&-48&\color{orangered}{ 64 }\\& & -12& 64& \color{orangered}{-64} \\ \hline &\color{blue}{3}&\color{blue}{-16}&\color{blue}{16}&\color{orangered}{0} \end{array} $$Bottom line represents the quotient $ \color{blue}{ 3x^{2}-16x+16 } $ with a remainder of $ \color{red}{ 0 } $.