Divide using synthetic division $$ ( 3x^{3}-2x^{2}-5x-7 ) \div ( x-3 ) $$
The synthetic division table is:
$$ \begin{array}{c|rrrr}3&3&-2&-5&-7\\& & 9& 21& \color{black}{48} \\ \hline &\color{blue}{3}&\color{blue}{7}&\color{blue}{16}&\color{orangered}{41} \end{array} $$The solution is:
$$ \dfrac{ 3x^{3}-2x^{2}-5x-7 }{ x-3 } = \color{blue}{3x^{2}+7x+16} ~+~ \dfrac{ \color{red}{ 41 } }{ x-3 } $$Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x -3 = 0 $ ( $ x = \color{blue}{ 3 } $ ) at the left.
$$ \begin{array}{c|rrrr}\color{blue}{3}&3&-2&-5&-7\\& & & & \\ \hline &&&& \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rrrr}3&\color{orangered}{ 3 }&-2&-5&-7\\& & & & \\ \hline &\color{orangered}{3}&&& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 3 } \cdot \color{blue}{ 3 } = \color{blue}{ 9 } $.
$$ \begin{array}{c|rrrr}\color{blue}{3}&3&-2&-5&-7\\& & \color{blue}{9} & & \\ \hline &\color{blue}{3}&&& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ -2 } + \color{orangered}{ 9 } = \color{orangered}{ 7 } $
$$ \begin{array}{c|rrrr}3&3&\color{orangered}{ -2 }&-5&-7\\& & \color{orangered}{9} & & \\ \hline &3&\color{orangered}{7}&& \end{array} $$Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 3 } \cdot \color{blue}{ 7 } = \color{blue}{ 21 } $.
$$ \begin{array}{c|rrrr}\color{blue}{3}&3&-2&-5&-7\\& & 9& \color{blue}{21} & \\ \hline &3&\color{blue}{7}&& \end{array} $$Step 5 : Add down last column: $ \color{orangered}{ -5 } + \color{orangered}{ 21 } = \color{orangered}{ 16 } $
$$ \begin{array}{c|rrrr}3&3&-2&\color{orangered}{ -5 }&-7\\& & 9& \color{orangered}{21} & \\ \hline &3&7&\color{orangered}{16}& \end{array} $$Step 6 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 3 } \cdot \color{blue}{ 16 } = \color{blue}{ 48 } $.
$$ \begin{array}{c|rrrr}\color{blue}{3}&3&-2&-5&-7\\& & 9& 21& \color{blue}{48} \\ \hline &3&7&\color{blue}{16}& \end{array} $$Step 7 : Add down last column: $ \color{orangered}{ -7 } + \color{orangered}{ 48 } = \color{orangered}{ 41 } $
$$ \begin{array}{c|rrrr}3&3&-2&-5&\color{orangered}{ -7 }\\& & 9& 21& \color{orangered}{48} \\ \hline &\color{blue}{3}&\color{blue}{7}&\color{blue}{16}&\color{orangered}{41} \end{array} $$Bottom line represents the quotient $ \color{blue}{ 3x^{2}+7x+16 } $ with a remainder of $ \color{red}{ 41 } $.