The synthetic division table is:
$$ \begin{array}{c|rrr}2&-1&0&-3\\& & -2& \color{black}{-4} \\ \hline &\color{blue}{-1}&\color{blue}{-2}&\color{orangered}{-7} \end{array} $$The solution is:
$$ \dfrac{ -x^{2}-3 }{ x-2 } = \color{blue}{-x-2} \color{red}{~-~} \dfrac{ \color{red}{ 7 } }{ x-2 } $$Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x -2 = 0 $ ( $ x = \color{blue}{ 2 } $ ) at the left.
$$ \begin{array}{c|rrr}\color{blue}{2}&-1&0&-3\\& & & \\ \hline &&& \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rrr}2&\color{orangered}{ -1 }&0&-3\\& & & \\ \hline &\color{orangered}{-1}&& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 2 } \cdot \color{blue}{ \left( -1 \right) } = \color{blue}{ -2 } $.
$$ \begin{array}{c|rrr}\color{blue}{2}&-1&0&-3\\& & \color{blue}{-2} & \\ \hline &\color{blue}{-1}&& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ 0 } + \color{orangered}{ \left( -2 \right) } = \color{orangered}{ -2 } $
$$ \begin{array}{c|rrr}2&-1&\color{orangered}{ 0 }&-3\\& & \color{orangered}{-2} & \\ \hline &-1&\color{orangered}{-2}& \end{array} $$Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 2 } \cdot \color{blue}{ \left( -2 \right) } = \color{blue}{ -4 } $.
$$ \begin{array}{c|rrr}\color{blue}{2}&-1&0&-3\\& & -2& \color{blue}{-4} \\ \hline &-1&\color{blue}{-2}& \end{array} $$Step 5 : Add down last column: $ \color{orangered}{ -3 } + \color{orangered}{ \left( -4 \right) } = \color{orangered}{ -7 } $
$$ \begin{array}{c|rrr}2&-1&0&\color{orangered}{ -3 }\\& & -2& \color{orangered}{-4} \\ \hline &\color{blue}{-1}&\color{blue}{-2}&\color{orangered}{-7} \end{array} $$Bottom line represents the quotient $ \color{blue}{ -x-2 } $ with a remainder of $ \color{red}{ -7 } $.