Question
Divide using synthetic division $$ ( 11x ) \div ( x-3 ) $$
Answer
The synthetic division table is:
$$ \begin{array}{c|rr}3&11&0\\& & \color{black}{33} \\ \hline &\color{blue}{11}&\color{orangered}{33} \end{array} $$The solution is:
$$ \dfrac{ 11x }{ x-3 } = \color{blue}{11} ~+~ \dfrac{ \color{red}{ 33 } }{ x-3 } $$Explanation
Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x -3 = 0 $ ( $ x = \color{blue}{ 3 } $ ) at the left.
$$ \begin{array}{c|rr}\color{blue}{3}&11&0\\& & \\ \hline && \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rr}3&\color{orangered}{ 11 }&0\\& & \\ \hline &\color{orangered}{11}& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 3 } \cdot \color{blue}{ 11 } = \color{blue}{ 33 } $.
$$ \begin{array}{c|rr}\color{blue}{3}&11&0\\& & \color{blue}{33} \\ \hline &\color{blue}{11}& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ 0 } + \color{orangered}{ 33 } = \color{orangered}{ 33 } $
$$ \begin{array}{c|rr}3&11&\color{orangered}{ 0 }\\& & \color{orangered}{33} \\ \hline &\color{blue}{11}&\color{orangered}{33} \end{array} $$Bottom line represents the quotient $ \color{blue}{ 11 } $ with a remainder of $ \color{red}{ 33 } $.
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