Question
Answer
$$\sqrt{72}+\sqrt{800}-\sqrt{18}=23\sqrt{2}$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}\sqrt{72}+\sqrt{800}-\sqrt{18}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} \htmlClass{explanationCircle explanationCircle3}{\textcircled {3}} } }}}6\sqrt{2}+20\sqrt{2}-3\sqrt{2} \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle4}{\textcircled {4}} } }}}23\sqrt{2}\end{aligned} $$ | |
| ① | $$ \sqrt{72} =
\sqrt{ 6 ^2 \cdot 2 } =
\sqrt{ 6 ^2 } \, \sqrt{ 2 } =
6 \sqrt{ 2 }$$ |
| ② | $$ \sqrt{800} =
\sqrt{ 20 ^2 \cdot 2 } =
\sqrt{ 20 ^2 } \, \sqrt{ 2 } =
20 \sqrt{ 2 }$$ |
| ③ | $$ - \sqrt{18} =
- \sqrt{ 3 ^2 \cdot 2 } =
- \sqrt{ 3 ^2 } \, \sqrt{ 2 } =
- 3 \sqrt{ 2 }$$ |
| ④ | Combine like terms |
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