Question
Answer
$$\sqrt{7}\cdot(10-4\sqrt{5})=10\sqrt{7}-4\sqrt{35}$$
Explanation
| $$ \begin{aligned}\sqrt{7}\cdot(10-4\sqrt{5})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}10\sqrt{7}-4\sqrt{35}\end{aligned} $$ | |
| ① | $$ \color{blue}{ \sqrt{7} } \cdot \left( 10- 4 \sqrt{5}\right) = \color{blue}{ \sqrt{7}} \cdot10+\color{blue}{ \sqrt{7}} \cdot- 4 \sqrt{5} = \\ = 10 \sqrt{7}- 4 \sqrt{35} $$ |
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