Question
Answer
$$\sqrt{63}+6-\sqrt{2}=3\sqrt{7}+6-\sqrt{2}$$
Explanation
| $$ \begin{aligned}\sqrt{63}+6-\sqrt{2}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3\sqrt{7}+6-\sqrt{2}\end{aligned} $$ | |
| ① | $$ \sqrt{63} =
\sqrt{ 3 ^2 \cdot 7 } =
\sqrt{ 3 ^2 } \, \sqrt{ 7 } =
3 \sqrt{ 7 }$$ |
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