Question
Answer
$$\sqrt{6}\cdot(-4\sqrt{2})=-8\sqrt{3}$$
Explanation
| $$ \begin{aligned}\sqrt{6}\cdot(-4\sqrt{2})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-8\sqrt{3}\end{aligned} $$ | |
| ① | $$ - 4 \sqrt{12} =
-4 \sqrt{ 2 ^2 \cdot 3 } =
-4 \sqrt{ 2 ^2 } \, \sqrt{ 3 } =
-4 \cdot 2 \sqrt{ 3 } =
-8 \sqrt{ 3 } $$ |
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