Question
Answer
$$\sqrt{6}\cdot\sqrt{1}-3\sqrt{8}=\sqrt{6}-6\sqrt{2}$$
Explanation
| $$ \begin{aligned}\sqrt{6}\cdot\sqrt{1}-3\sqrt{8}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\sqrt{6}-6\sqrt{2}\end{aligned} $$ | |
| ① | $$ - 3 \sqrt{8} =
-3 \sqrt{ 2 ^2 \cdot 2 } =
-3 \sqrt{ 2 ^2 } \, \sqrt{ 2 } =
-3 \cdot 2 \sqrt{ 2 } =
-6 \sqrt{ 2 } $$ |
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