| $$ \begin{aligned}\sqrt{6}\cdot\frac{\sqrt{14}}{15}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{2\sqrt{21}}{15}\end{aligned} $$ | |
| ① | $$ \color{blue}{ \sqrt{6} } \cdot \sqrt{14} = 2 \sqrt{21} $$$$ \color{blue}{ 1 } \cdot 15 = 15 $$ |