Question
Answer
$$\sqrt{6}\cdot(\sqrt{3}+\sqrt{10})=3\sqrt{2}+2\sqrt{15}$$
Explanation
| $$ \begin{aligned}\sqrt{6}\cdot(\sqrt{3}+\sqrt{10})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}3\sqrt{2}+2\sqrt{15}\end{aligned} $$ | |
| ① | $$ \color{blue}{ \sqrt{6} } \cdot \left( \sqrt{3} + \sqrt{10}\right) = \color{blue}{ \sqrt{6}} \cdot \sqrt{3}+\color{blue}{ \sqrt{6}} \cdot \sqrt{10} = \\ = 3 \sqrt{2} + 2 \sqrt{15} $$ |
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