Question
Answer
$$\sqrt{6}\cdot(7+3\sqrt{3})=7\sqrt{6}+9\sqrt{2}$$
Explanation
| $$ \begin{aligned}\sqrt{6}\cdot(7+3\sqrt{3})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}7\sqrt{6}+9\sqrt{2}\end{aligned} $$ | |
| ① | $$ \color{blue}{ \sqrt{6} } \cdot \left( 7 + 3 \sqrt{3}\right) = \color{blue}{ \sqrt{6}} \cdot7+\color{blue}{ \sqrt{6}} \cdot 3 \sqrt{3} = \\ = 7 \sqrt{6} + 9 \sqrt{2} $$ |
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