| $$ \begin{aligned}\sqrt{6}\cdot2\sqrt{15}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}6\sqrt{10}\end{aligned} $$ | |
| ① | $$ 2 \sqrt{90} =
2 \sqrt{ 3 ^2 \cdot 10 } =
2 \sqrt{ 3 ^2 } \, \sqrt{ 10 } =
2 \cdot 3 \sqrt{ 10 } =
6 \sqrt{ 10 } $$ |