Question
Answer
$$\sqrt{5}\cdot(7-\sqrt{14})=7\sqrt{5}-\sqrt{70}$$
Explanation
| $$ \begin{aligned}\sqrt{5}\cdot(7-\sqrt{14})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}7\sqrt{5}-\sqrt{70}\end{aligned} $$ | |
| ① | $$ \color{blue}{ \sqrt{5} } \cdot \left( 7- \sqrt{14}\right) = \color{blue}{ \sqrt{5}} \cdot7+\color{blue}{ \sqrt{5}} \cdot- \sqrt{14} = \\ = 7 \sqrt{5}- \sqrt{70} $$ |
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