Question
Answer
$$\sqrt{5}\cdot(4-\sqrt{5})=4\sqrt{5}-5$$
Explanation
| $$ \begin{aligned}\sqrt{5}\cdot(4-\sqrt{5})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}4\sqrt{5}-5\end{aligned} $$ | |
| ① | $$ \color{blue}{ \sqrt{5} } \cdot \left( 4- \sqrt{5}\right) = \color{blue}{ \sqrt{5}} \cdot4+\color{blue}{ \sqrt{5}} \cdot- \sqrt{5} = \\ = 4 \sqrt{5}-5 $$ |
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