Question
Answer
$$\sqrt{5}\cdot(-8+\sqrt{2})=-8\sqrt{5}+\sqrt{10}$$
Explanation
| $$ \begin{aligned}\sqrt{5}\cdot(-8+\sqrt{2})& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-8\sqrt{5}+\sqrt{10}\end{aligned} $$ | |
| ① | $$ \color{blue}{ \sqrt{5} } \cdot \left( -8 + \sqrt{2}\right) = \color{blue}{ \sqrt{5}} \cdot-8+\color{blue}{ \sqrt{5}} \cdot \sqrt{2} = \\ = - 8 \sqrt{5} + \sqrt{10} $$ |
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