Question
Answer
$$\sqrt{4}\cdot\sqrt{2}+\sqrt{2}\cdot\sqrt{3}=2\sqrt{2}+\sqrt{6}$$
Explanation
| $$ \begin{aligned}\sqrt{4}\cdot\sqrt{2}+\sqrt{2}\cdot\sqrt{3}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2\sqrt{2}+\sqrt{6}\end{aligned} $$ | |
| ① | $$ \sqrt{8} =
\sqrt{ 2 ^2 \cdot 2 } =
\sqrt{ 2 ^2 } \, \sqrt{ 2 } =
2 \sqrt{ 2 }$$ |
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